[LeetCode] ZigZag Conversion
Problem
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H NA P L S I I GY I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
Note
很奇葩的题目,PAYPAL IS HIRING.
先将s转化为字符数组c,便于操作。
再看nRows要求转化为多少行,就建立多大的StringBuilder数组sb[]。注意,建立完之后要用for循环对每一个StringBuilder[i]初始化:sb[i] = new StringBuilder();
然后用指针i循环字符数组c:顺序从0到nRows-1每一行放入一个字符c[i++],然后逆序从nRows-2到1每一行放入一个字符c[i++],直到i == c.length.
以上就将竖向ZigZag形式的字符串以横向读取顺序存入了数组sb中,将sb[i]中的所有字符串都合并到sb[0]中即可。
Solution
public class Solution { public String convert(String s, int nRows) { char[] c = s.toCharArray(); int len = c.length; StringBuffer[] sb = new StringBuffer[nRows]; for (int i = 0; i = 1 && i < len; idx--) // obliquely up sb[idx].append(c[i++]); } for (int idx = 1; idx < sb.length; idx++) sb[0].append(sb[idx]); return sb[0].toString(); }}
关键字:java, string
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