文章目录

• 一.前言🚀
• 二.游戏逻辑✈🚀
• 三.代码实现🚀
• • 1.test.c🚗
  • 2.game.h🚓
  • 3.game.c🚕
• 四.游戏功能具体分析🚀
• • 1.棋盘的初始化🚙
  • 2.棋盘的打印🚑
  • 3.玩家下棋🚒
  • 4.电脑下棋🚍
  • • 4.1简单模式🚘
    • 4.2困难模式🚖
  • 5.判断棋盘满没满🚅
  • 6.判断游戏输赢🚃
• 五.总结🚀

一.前言🚀

大家好，首先祝大家五一快乐🎈🎈🎈🎈🎈🎈，当然有很多大学生像作者一样五一并没有放假，说多了都是泪啊😭，不过没事，我们还有周末！废话不多说了，今天我们一起来研究一下三子棋，虽然在c站三子棋已经烂大街了，但是每个人都有自己与众不同的地方，值得我们学习。所以我们可以博采众长，吸收别人优秀的地方，提高自己的水平。

二.游戏逻辑✈🚀

我们在写一个项目的时候，如果这个项目非常复杂，不建议大家上来就干代码的，因为你有很大的可能会出错。我们应该仔细思考游戏的逻辑，如何实现这个项目。

1.我们需要一个菜单控制游戏，让玩家做出选择

2.游戏最好可以让玩家一直玩，除非玩家退出游戏

3.三子棋需要一个棋盘，我们打印一个棋盘（通过二维数组）

4.玩家下棋，输入坐标（也可以电脑先下棋）

5.打印棋盘，观察坐标，（是否有错误）

6.电脑下棋，打印棋盘，这部分我们可以优化一下，让我们很难赢电脑

7.判断输赢，打印棋盘，观察坐标

三.代码实现🚀

当我们写的代码比较多的时候，建议大家使用模块化的设计，我们这里分成三个部分：

test.c

主函数部分，对游戏的逻辑进行测试运行

game.h

库函数头文件的包含

行列的自定义设置

函数的定义

game.c

游戏逻辑的具体实现

1.test.c🚗

#define _CRT_SECURE_NO_WARNINGS 1#include"game.h"
void menu()
{printf("**************************************\n");printf("******** 1. play（智能模式） *********\n");printf("******** 2. play（智障模式） *********\n");printf("******** 0. exit（退出游戏） *********\n");printf("**************************************\n");}
void game1()
{	//存储数据 - 二维数组char board[ROW][COL] = { 0 };//初始化棋盘 - 初始化空格initBoard(board, ROW, COL);//打印棋盘 - 本质是打印数组的内容displayBoard(board, ROW, COL);//下棋char ret = 0;while(1){playerMove(board, ROW, COL);displayBoard(board, ROW, COL);//判断玩家是否赢得游戏ret = isWin(board, ROW, COL);if(ret != 'c'){break;}		computerMove(board, ROW, COL);displayBoard(board, ROW, COL);//判断电脑是否赢得游戏ret = isWin(board, ROW, COL);if (ret != 'c'){break;}}switch (ret){case 'O':printf("你赢了,也就一般般吧\n");break;case 'X':printf("你竟然输给了人工智障，哈哈\n");break;case 'p':printf("平局，好好反思一下你自己\n");break;displayBoard(board, ROW, COL);}//效果差不多/*if (ret == 'o'){printf("玩家赢了\n");}else if (ret == 'x'){printf("电脑赢了\n");}else{printf("平局\n");}*/
}
void game2()
{	//存储数据 - 二维数组char board[ROW][COL] = { 0 };//初始化棋盘 - 初始化空格initBoard(board, ROW, COL);//打印棋盘 - 本质是打印数组的内容displayBoard(board, ROW, COL);//下棋char ret = 0;while (1){		SmartComputerMove(board, ROW, COL);displayBoard(board, ROW, COL);ret = isWin(board, ROW, COL);//判断电脑是否赢得游戏if (ret != 'c'){break;}playerMove(board, ROW, COL);displayBoard(board, ROW, COL);//判断玩家是否赢得游戏ret = isWin(board, ROW, COL);if (ret != 'c'){break;}}switch (ret){case 'O':printf("您赢了,就算是阿尔法狗也不是您的对手\n");break;case 'X':printf("你输了，没事，等于你已经和大神过过手了\n");break;case 'p':printf("平局，小伙子，你非常有前途\n");break;displayBoard(board, ROW, COL);}
}int main()
{int input = 0;srand((unsigned int)time(NULL));do{menu();printf("请选择模式:>");printf("\n人工智障：1 | 人工智能：2 | 退出游戏：0\n");scanf("%d", &input);switch (input){case 1:game1();break;case 2:game2();break;case 0:printf("退出游戏\n");break;default:printf("输入错误，请重新输入\n");break;}} while (input);return 0;
}

2.game.h🚓

//防止头文件被重复包含
#pragma once
//头文件的包含
#include
#include
#include
//定义行和列(可以随意改变)
#define ROW 3
#define COL 3
//初始化棋盘
void initBoard(char board[ROW][COL], int row, int col);
//打印棋盘的函数
void displayBoard(char board[ROW][COL], int row, int col);
//玩家下棋
void playerMove(char board[ROW][COL], int row, int col);
//电脑下棋
//普通模式
void computerMove(char board[ROW][COL], int row, int col);
//困难模式
void SmartComputerMove(char board[ROW][COL], int row, int col);
//判断棋盘满没满
int isFull(char board[ROW][COL], int row, int col);
//1.玩家赢 - O
//2.电脑赢 - X
//3.平局 - p
//4.游戏继续 - c
//判断输赢
char isWin(char board[ROW][COL], int row, int col);

3.game.c🚕

#define _CRT_SECURE_NO_WARNINGS 1#include"game.h"void initBoard(char board[ROW][COL], int row, int col)
{for (int i = 0; i < row; i++){for (int j = 0; j < col; j++){board[i][j] = ' ';}}
}
void displayBoard(char board[ROW][COL], int row, int col)
{int i = 0;int j = 0;for (i = 0; i < row; i++){for (j = 0; j < col; j++){printf(" %c ", board[i][j]);if (j < col - 1)printf("|");}printf("\n");if (i < row - 1){for(int j = 0; j < col; j++){printf("---");if (j < col - 1){printf("|");}}	}printf("\n");}
}
void playerMove(char board[ROW][COL], int row, int col)
{int x = 0;int y = 0;printf("玩家走:>\n");while(1){ printf("请输入下棋坐标:>");scanf("%d %d", &x, &y);if (x > 0 && x <= row && y > 0 && y <= col){//判断坐标是否被占用if (board[x - 1][y - 1] == ' '){board[x - 1][y - 1] = 'O';break;}else{printf("坐标已被占用，请重新输入\n");break;}}else{printf("坐标错误，请重新输入\n");}}	
}void computerMove(char board[ROW][COL], int row, int col)
{int x = 0;int y = 0;printf("电脑走:>\n");while (1){x = rand() % row;y = rand() % col;//不用判断合法性if(board[x][y] == ' '){board[x][y] = 'X';break;}}	
}
int isFull(char board[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){if(board[i][j] == ' '){return 0;//棋盘没满}		}}return 1;//棋盘满了
}
char isWin(char board[ROW][COL], int row, int col)
{//判断三行for (int i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] != ' '){return board[i][1];}}//判断三列for (int j = 0; j < col; j++){if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] != ' '){return board[0][j];}}//判断对角线if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' '){return board[0][0];}if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' '){return board[0][2];}//判断平局int ret = isFull(board, row, col);if (ret == 1){return 'p';}return 'c';
}void SmartComputerMove(char board[ROW][COL], int row, int col)
{int i = 0;int j = 0;//判断每一行是否有两个相连的棋子，如果有，且第三个棋格为空，则落棋for (i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][0] == 'X' && board[i][2] == ' '){board[i][2] = 'X';}if (board[i][0] == board[i][2] && board[i][0] == 'X' && board[i][1] == ' '){board[i][1] = 'X';}if (board[i][1] == board[i][2] && board[i][1] == 'X' && board[i][0] == ' '){board[i][0] = 'X';}}//判断每一列是否有两个相连的棋子，如果有，且第三个棋格为空，则落棋for (j = 0; j < col; j++){if (board[0][j] == board[1][j] && board[0][j] == 'X' && board[2][j] == ' '){board[2][j] = 'X';}if (board[0][j] == board[2][j] && board[0][j] == 'X' && board[1][j] == ' '){board[1][j] = 'X';}if (board[1][j] == board[2][j] && board[1][j] == 'X' && board[0][j] == ' '){board[0][j] = 'X';}}//判断两条对角线是否有两个相连的棋子，如果有，且第三个棋格为空，则落棋{//第一条if (board[0][0] == board[1][1] && board[0][0] == 'X' && board[2][2] == ' '){board[2][2] = 'X';}if (board[0][0] == board[2][2] && board[0][0] == 'X' && board[1][1] == ' '){board[1][1] = 'X';}if (board[1][1] == board[2][2] && board[1][1] == 'X' && board[0][0] == ' '){board[0][0] = 'X';}//第二条if (board[0][2] == board[1][1] && board[0][2] == 'X' && board[2][0] == ' '){board[2][0] = 'X';}if (board[0][2] == board[2][0] && board[0][2] == 'X' && board[1][1] == ' '){board[1][1] = 'X';}if (board[1][1] == board[2][0] && board[1][1] == 'X' && board[0][2] == ' '){board[0][2] = 'X';		}//如果上面都没落子，说明不符合赢的条件int i = 0;int j = 0;//判断每一行是否有两个相连的棋子，如果有，且第三个棋格为空，则堵棋for (i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][0] == 'O' && board[i][2] == ' '){board[i][2] = 'X';goto end;}if (board[i][0] == board[i][2] && board[i][0] == 'O' && board[i][1] == ' '){board[i][1] = 'X';goto end;}if (board[i][1] == board[i][2] && board[i][1] == 'O' && board[i][0] == ' '){board[i][0] = 'X';goto end;}}//判断每一列是否有两个相连的棋子，如果有，且第三个棋格为空，则堵棋for (j = 0; j < col; j++){if (board[0][j] == board[1][j] && board[0][j] == 'O' && board[2][j] == ' '){board[2][j] = 'X';goto end;}if (board[0][j] == board[2][j] && board[0][j] == 'O' && board[1][j] == ' '){board[1][j] = 'X';goto end;}if (board[1][j] == board[2][j] && board[1][j] == 'O' && board[0][j] == ' '){board[0][j] = 'X';goto end;}}//判断两条对角线是否有两个相连的棋子，如果有，且第三个棋格为空，则堵棋{//第一条if (board[0][0] == board[1][1] && board[0][0] == 'O' && board[2][2] == ' '){board[2][2] = 'X';goto end;}if (board[0][0] == board[2][2] && board[0][0] == 'O' && board[1][1] == ' '){board[1][1] = 'X';goto end;}if (board[1][1] == board[2][2] && board[1][1] == 'O' && board[0][0] == ' '){board[0][0] = 'X';goto end;}//第二条if (board[0][2] == board[1][1] && board[0][2] == 'O' && board[2][0] == ' '){board[2][0] = 'X';goto end;}if (board[0][2] == board[2][0] && board[0][2] == 'O' && board[1][1] == ' '){board[1][1] = 'X';goto end;}if (board[1][1] == board[2][0] && board[1][1] == 'O' && board[0][2] == ' '){board[0][2] = 'X';goto end;}//如果上面都没返回，说明不符合堵棋,下棋的条件else{computerMove(board, ROW, COL);}}}int ret = 0;end://判断平局ret = isFull(board, row, col);if (ret == 1){return 'p';}return 'c';
}

四.游戏功能具体分析🚀

1.棋盘的初始化🚙

void initBoard(char board[ROW][COL], int row, int col)
{for (int i = 0; i < row; i++){for (int j = 0; j < col; j++){board[i][j] = ' ';}}
}

2.棋盘的打印🚑

void displayBoard(char board[ROW][COL], int row, int col)
{int i = 0;int j = 0;for (i = 0; i < row; i++){for (j = 0; j < col; j++){printf(" %c ", board[i][j]);if (j < col - 1)printf("|");}printf("\n");if (i < row - 1){for(int j = 0; j < col; j++){printf("---");if (j < col - 1){printf("|");}}	}printf("\n");}
}

3.玩家下棋🚒

void playerMove(char board[ROW][COL], int row, int col)
{int x = 0;int y = 0;printf("玩家走:>\n");while(1){ printf("请输入下棋坐标:>");scanf("%d %d", &x, &y);if (x > 0 && x <= row && y > 0 && y <= col){//判断坐标是否被占用if (board[x - 1][y - 1] == ' '){board[x - 1][y - 1] = 'O';break;}else{printf("坐标已被占用，请重新输入\n");break;}}else{printf("坐标错误，请重新输入\n");}}	
}

4.电脑下棋🚍

4.1简单模式🚘

void computerMove(char board[ROW][COL], int row, int col)
{int x = 0;int y = 0;printf("电脑走:>\n");while (1){x = rand() % row;y = rand() % col;//不用判断合法性if(board[x][y] == ' '){board[x][y] = 'X';break;}}	
}

4.2困难模式🚖

void SmartComputerMove(char board[ROW][COL], int row, int col)
{int i = 0;int j = 0;//判断每一行是否有两个相连的棋子，如果有，且第三个棋格为空，则落棋for (i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][0] == 'X' && board[i][2] == ' '){board[i][2] = 'X';}if (board[i][0] == board[i][2] && board[i][0] == 'X' && board[i][1] == ' '){board[i][1] = 'X';}if (board[i][1] == board[i][2] && board[i][1] == 'X' && board[i][0] == ' '){board[i][0] = 'X';}}//判断每一列是否有两个相连的棋子，如果有，且第三个棋格为空，则落棋for (j = 0; j < col; j++){if (board[0][j] == board[1][j] && board[0][j] == 'X' && board[2][j] == ' '){board[2][j] = 'X';}if (board[0][j] == board[2][j] && board[0][j] == 'X' && board[1][j] == ' '){board[1][j] = 'X';}if (board[1][j] == board[2][j] && board[1][j] == 'X' && board[0][j] == ' '){board[0][j] = 'X';}}//判断两条对角线是否有两个相连的棋子，如果有，且第三个棋格为空，则落棋{//第一条if (board[0][0] == board[1][1] && board[0][0] == 'X' && board[2][2] == ' '){board[2][2] = 'X';}if (board[0][0] == board[2][2] && board[0][0] == 'X' && board[1][1] == ' '){board[1][1] = 'X';}if (board[1][1] == board[2][2] && board[1][1] == 'X' && board[0][0] == ' '){board[0][0] = 'X';}//第二条if (board[0][2] == board[1][1] && board[0][2] == 'X' && board[2][0] == ' '){board[2][0] = 'X';}if (board[0][2] == board[2][0] && board[0][2] == 'X' && board[1][1] == ' '){board[1][1] = 'X';}if (board[1][1] == board[2][0] && board[1][1] == 'X' && board[0][2] == ' '){board[0][2] = 'X';		}//如果上面都没落子，说明不符合赢的条件int i = 0;int j = 0;//判断每一行是否有两个相连的棋子，如果有，且第三个棋格为空，则堵棋for (i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][0] == 'O' && board[i][2] == ' '){board[i][2] = 'X';goto end;//防止多次落子的问题}if (board[i][0] == board[i][2] && board[i][0] == 'O' && board[i][1] == ' '){board[i][1] = 'X';goto end;}if (board[i][1] == board[i][2] && board[i][1] == 'O' && board[i][0] == ' '){board[i][0] = 'X';goto end;}}//判断每一列是否有两个相连的棋子，如果有，且第三个棋格为空，则堵棋for (j = 0; j < col; j++){if (board[0][j] == board[1][j] && board[0][j] == 'O' && board[2][j] == ' '){board[2][j] = 'X';goto end;}if (board[0][j] == board[2][j] && board[0][j] == 'O' && board[1][j] == ' '){board[1][j] = 'X';goto end;}if (board[1][j] == board[2][j] && board[1][j] == 'O' && board[0][j] == ' '){board[0][j] = 'X';goto end;}}//判断两条对角线是否有两个相连的棋子，如果有，且第三个棋格为空，则堵棋{//第一条if (board[0][0] == board[1][1] && board[0][0] == 'O' && board[2][2] == ' '){board[2][2] = 'X';goto end;}if (board[0][0] == board[2][2] && board[0][0] == 'O' && board[1][1] == ' '){board[1][1] = 'X';goto end;}if (board[1][1] == board[2][2] && board[1][1] == 'O' && board[0][0] == ' '){board[0][0] = 'X';goto end;}//第二条if (board[0][2] == board[1][1] && board[0][2] == 'O' && board[2][0] == ' '){board[2][0] = 'X';goto end;}if (board[0][2] == board[2][0] && board[0][2] == 'O' && board[1][1] == ' '){board[1][1] = 'X';goto end;}if (board[1][1] == board[2][0] && board[1][1] == 'O' && board[0][2] == ' '){board[0][2] = 'X';goto end;}//如果上面都没返回，说明不符合堵棋,下棋的条件else{computerMove(board, ROW, COL);}}}int ret = 0;end://判断平局ret = isFull(board, row, col);if (ret == 1){return 'p';}return 'c';
}

5.判断棋盘满没满🚅

int isFull(char board[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){if(board[i][j] == ' '){return 0;//棋盘没满}		}}return 1;//棋盘满了
}

6.判断游戏输赢🚃

char isWin(char board[ROW][COL], int row, int col)
{//判断三行for (int i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] != ' '){return board[i][1];}}//判断三列for (int j = 0; j < col; j++){if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] != ' '){return board[0][j];}}//判断对角线if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' '){return board[0][0];}if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' '){return board[0][2];}//判断平局int ret = isFull(board, row, col);if (ret == 1){return 'p';}return 'c';
}

五.总结🚀

我们可以发现简单模式下，电脑的下法是非常笨拙的，因为是随机的坐标。我们可以改一下，比如困难模式，用穷举的方法，判断我方是否有两颗棋子在一条线上，如果有则堵死；并且判断电脑的棋子是否有两颗在一条线上，如果有则落子。一定程度上增加了难度，不太容易赢，平局比较多。因为电脑前两颗棋子是随机的，所以也就是看运气。感兴趣的小伙伴可以复制过去体验一下，可能会有BUG，我暂时还没有发现！！！如果你发现了，请一定联系我改正。另外，这个程序只适用于三子棋，其实也可以改，不过我懒写的了，你可以搜一下，等以后闲了再说吧，孩子要好好学习了，不然要挂科了！！！😭😭😭

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