Java黑皮书课后题第9章：*9.11（代数：2*2的线性方程）为一个2*2的线性方程设计一个名为LinearEquation的类

• 题目
• • 破题
• 代码
• • Test10
  • Test11_LinearEquation
  • 运行结果
• UML图

题目

破题

Test11：测试程序
Test11_LinearEquation：实现题目要求

点击跳转练习题3.3

代码

Test10

import java.util.Scanner;public class Test11 {public static void main(String[] args) {// 获取用户输入Scanner input = new Scanner(System.in);System.out.println("Enter a, b, c, d, e, f: ");double a = input.nextInt(), b = input.nextInt(), c = input.nextInt();double d = input.nextInt(), e = input.nextInt(), f = input.nextInt();// 传入构造方法Test11_LinearEquation le = new Test11_LinearEquation(a, b, c, d, e, f);// 判断是否有结果boolean bool = le.isSolvable();if (bool){System.out.println("x is " + le.getX() + " and y is " + le.getY());} elseSystem.out.println("The equation has no solution");}
}

Test11_LinearEquation

public class Test11_LinearEquation {private double a, b, c, d, e, f;// 构造方法public Test11_LinearEquation (double a, double b, double c, double d, double e, double f){this.a = a;this.b = b;this.c = c;this.d = d;this.e = e;this.f = f;}// getterpublic double getA() {return a;}public double getB() {return b;}public double getC() {return c;}public double getD() {return d;}public double getE() {return e;}public double getF() {return f;}// isSolvable方法public boolean isSolvable(){boolean bool = false;if (a * d - b * c != 0){bool = true;}return bool;}// getX和getYpublic double getX(){return (e * d - b * f) / (a * d - b * c);}public double getY(){return (a * f - e * c) / (a * d - b * c);}
}

运行结果

Enter a, b, c, d, e, f: 
1 2 3 4 5 6
x is -4.0 and y is 4.5

UML图

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