2020 ciscn 东北分区赛 re题解

唉，居然没师傅出re题，悲伤
此题考点在于抓取或解密出迷宫，这里我用的原函数进行生成，改改几个定义就可以输出迷宫了：

#include
#include
#include 
#include
#include
#include
//#+OXJ xnB1 QWT4 9cnW cGFB ZOjn yfZo ZV1m 7+/v /29t f2c= 
__int64 sub_556D3A76F833(unsigned int* a1, int a2)
{int v3; // eaxint v4[48]; // [rsp+10h] [rbp-E0h]int v5; // [rsp+D0h] [rbp-20h]int v6; // [rsp+DCh] [rbp-14h]int k; // [rsp+E0h] [rbp-10h]int j; // [rsp+E4h] [rbp-Ch]int i; // [rsp+E8h] [rbp-8h]unsigned int v10; // [rsp+ECh] [rbp-4h]if (a2 == 1)return *a1;v10 = 0;memset(v4, 0, sizeof(v4));v5 = 0;for (i = 0; i < a2; ++i){for (j = 0; j < a2 - 1; ++j){for (k = 0; k < a2 - 1; ++k){if (k < i)v3 = k;elsev3 = k + 1;v4[k + 7LL * j] = a1[7 * (j + 1LL) + v3];}}v6 = sub_556D3A76F833((unsigned int*)v4, a2 - 1);if (i & 1)v10 -= v6 * a1[i];elsev10 += v6 * a1[i];}return v10;
}unsigned __int64 __fastcall sub_556D3A76F99D(__int64 a1, int a2, unsigned int* a3)
{unsigned __int64 result; // raxsigned __int64 v4; // rdxsigned __int64 v5; // rdxint v6; // eaxsigned __int64 v7; // rbxint v8; // eaxunsigned int* v9; // [rsp+8h] [rbp-108h]int v10[52]; // [rsp+20h] [rbp-F0h]int l; // [rsp+F0h] [rbp-20h]int k; // [rsp+F4h] [rbp-1Ch]int j; // [rsp+F8h] [rbp-18h]int i; // [rsp+FCh] [rbp-14h]v9 = a3;if (a2 == 1){result = (unsigned __int64)a3;*a3 = 1;}else{for (i = 0; ; ++i){result = (unsigned int)i;if (i >= a2)break;for (j = 0; j < a2; ++j){for (k = 0; k < a2 - 1; ++k){for (l = 0; l < a2 - 1; ++l){if (k < i)v4 = 28LL * k;elsev4 = 28LL * (k + 1);v5 = a1 + v4;if (l < j)v6 = l;elsev6 = l + 1;v10[l + 7LL * k] = *(uint32_t*)(v5 + 4LL * v6);}}v7 = (signed __int64)&v9[7 * j];v8 = sub_556D3A76F833((unsigned int*)v10, a2 - 1);*(unsigned int*)(v7 + 4LL * i) = v8;if ((j + i) % 2 == 1)v9[7 * j + i] = -v9[7 * j + i];}}}return result;
}
signed __int64 __fastcall sub_556D3A76FB98(__int64 a1, int a2, __int64 a3)
{__int64 v4; // [rsp+8h] [rbp-E8h]unsigned int v5[49]; // [rsp+20h] [rbp-D0h]int v6; // [rsp+E4h] [rbp-Ch]int j; // [rsp+E8h] [rbp-8h]int i; // [rsp+ECh] [rbp-4h]v4 = a3;v6 = sub_556D3A76F833((unsigned int*)a1, a2);if (!v6)return 0LL;sub_556D3A76F99D(a1, a2, v5);for (i = 0; i < a2; ++i){for (j = 0; j < a2; ++j)*(unsigned int*)(28LL * i + v4 + 4LL * j) = v5[j + 7LL * i] / v6;}return 1LL;
}__int64 __fastcall sub_556D3A76F7A2(__int64 a1, signed int a2, __int64 a3)
{__int64 result; // raxsigned int j; // [rsp+20h] [rbp-8h]signed int i; // [rsp+24h] [rbp-4h]for (i = 0; ; ++i){result = (unsigned int)i;if (i >= a2)break;for (j = 0; j < a2; ++j)*(unsigned int*)(28LL * i + a3 + 4LL * j) = *(unsigned int*)(28LL * j + a1 + 4LL * (a2 - i - 1));}return result;
}
unsigned char unk_556D3A773160[255] = { 0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0x3,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0x0,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0x2,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0xfe,0xff,0xff,0xff,0x1,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x0,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0x3,0x0,0x0,0x0,0xfc,0xff,0xff,0xff,0x2,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x1,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0x1,0x0,0x0,0x0,0xfe,0xff,0xff,0xff,0x1,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0x0,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0x0,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0x2,0x0,0x0,0x0,0xff,0xff,0xff,0xff,0x1,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0 };
int main()
{
//    char v8[255] = { 2,0,0,0,255,0,0,0,0,0,0,0,254,0,0,0,1,0,0,0,255,0,0,0,0,0,0,0,
//1,0,0,0,255,0,0,0,0,0,0,0,255,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,
//0,0,0,0,0,0,0,0,0,0,0,0,255,0,0,0,0,0,0,0,255,0,0,0,1,0,0,0,
//255,0,0,0,1,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,1,0,0,0,255,0,0,0,
//3,0,0,0,254,0,0,0,255,0,0,0,252,0,0,0,1,0,0,0,254,0,0,0,2,0,0,0,
//254,0,0,0,1,0,0,0,1,0,0,0,3,0,0,0,255,0,0,0,1,0,0,0,255,0,0,0,
//255,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,255,0,0,0,1,0,0,0,0,0,0,0 };char v8;memset(&v8, 0, 0xC0uLL);char v6;memset(&v6, 0, 0xC0uLL);int d;//  scanf("%d", &d);sub_556D3A76F7A2((__int64)&unk_556D3A773160, 7, (__int64)&v8);//for (int i = 0; i < 0xc0; i++)//{//    printf("%d ", *(&v8 + i));//    if (i % 28 == 0 && i != 0)//        printf("\n");//}printf("\n\n");sub_556D3A76FB98((__int64)&v8, 7, (__int64)&v6);for (int i = 0; i <= 0xc4; i++){printf("%d ", *(&v6+i));if (i % 28 == 0 && i!=0)printf("\n");}
}

然后解密即可。

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