PHP 2种方法判断身份证是否有效

 介绍2种方法 , 第一种是我获取远程的网页数据 , 然后正则处理, 返回你需要的数据, 你可以直接复制, 参数替换好打印

$IDNumber  $judge  $NativePlace  $birth $Gender 这几个参数看看

               $url = "  //$身份证替换你自己变量 $list = file_get_contents("compress.zlib://".$url);$list= mb_convert_encoding($list, 'UTF-8', 'UTF-8,GBK,GB2312,BIG5');$res = preg_replace("/(\s|\ \;|　|\xc2\xa0)/", " ", strip_tags($list));$IDNumber = substr($res,strripos($res,"证件号码")+12, 18);$judge = substr($res,strripos($res,"判断参考")+12, 36);$NativePlace = substr($res,strripos($res,"发 证 地")+11, 9);$birth = substr($res,strripos($res,"出生日期")+12, 19);$Gender = substr($res,strripos($res,"性别年龄")+12,12 );if ($judge === "身份证号码校验为合法号码") $status = true;else  $status = false;dump($IDNumber);dump($judge);dump($NativePlace );dump($birth );

另一种就是正则匹配 , 只会返回布尔值

/*** 判断是否为合法的身份证号码* @param $mobile* @return int*/
function isCreditNo($vStr){$vCity = array('11','12','13','14','15','21','22','23','31','32','33','34','35','36','37','41','42','43','44','45','46','50','51','52','53','54','61','62','63','64','65','71','81','82','91');if (!preg_match('/^([\d]{17}[xX\d]|[\d]{15})$/', $vStr)) return false;if (!in_array(substr($vStr, 0, 2), $vCity)) return false;$vStr = preg_replace('/[xX]$/i', 'a', $vStr);$vLength = strlen($vStr);if ($vLength == 18) {$vBirthday = substr($vStr, 6, 4) . '-' . substr($vStr, 10, 2) . '-' . substr($vStr, 12, 2);} else {$vBirthday = '19' . substr($vStr, 6, 2) . '-' . substr($vStr, 8, 2) . '-' . substr($vStr, 10, 2);}if (date('Y-m-d', strtotime($vBirthday)) != $vBirthday) return false;if ($vLength == 18) {$vSum = 0;for ($i = 17 ; $i >= 0 ; $i--) {$vSubStr = substr($vStr, 17 - $i, 1);$vSum += (pow(2, $i) % 11) * (($vSubStr == 'a') ? 10 : intval($vSubStr , 11));}if($vSum % 11 != 1) return false;}return true;
}

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