经纬度求距离求与正北方向的夹角(方向角)
转载地址:http://blog.csdn.net/liang5630/article/details/42775997
package com.liang.test;public class AngleUtil {public static void main(String[] args) {MyLatLng A=new MyLatLng(113.249648,23.401553);MyLatLng B=new MyLatLng(113.246033,23.403362);System.out.println(getAngle(A,B));}/*** 求B点经纬度* @param A 已知点的经纬度,* @param distance AB两地的距离 单位km* @param angle AB连线与正北方向的夹角(0~360)* @return B点的经纬度*/public static MyLatLng getMyLatLng(MyLatLng A,double distance,double angle){double dx = distance*1000*Math.sin(Math.toRadians(angle));double dy= distance*1000*Math.cos(Math.toRadians(angle));double bjd=(dx/A.Ed+A.m_RadLo)*180./Math.PI;double bwd=(dy/A.Ec+A.m_RadLa)*180./Math.PI;return new MyLatLng(bjd, bwd);}/*** 获取AB连线与正北方向的角度* @param A A点的经纬度* @param B B点的经纬度* @return AB连线与正北方向的角度(0~360)*/public static double getAngle(MyLatLng A,MyLatLng B){double dx=(B.m_RadLo-A.m_RadLo)*A.Ed;double dy=(B.m_RadLa-A.m_RadLa)*A.Ec;double angle=0.0;angle=Math.atan(Math.abs(dx/dy))*180./Math.PI; double dLo=B.m_Longitude-A.m_Longitude;double dLa=B.m_Latitude-A.m_Latitude;if(dLo>0&&dLa<=0){angle=(90.-angle)+90;}else if(dLo<=0&&dLa<0){angle=angle+180.;}else if(dLo<0&&dLa>=0){angle= (90.-angle)+270;}return angle;}static class MyLatLng {final static double Rc=6378137;final static double Rj=6356725;double m_LoDeg,m_LoMin,m_LoSec;double m_LaDeg,m_LaMin,m_LaSec;double m_Longitude,m_Latitude;double m_RadLo,m_RadLa;double Ec;double Ed;public MyLatLng(double longitude,double latitude){m_LoDeg=(int)longitude;m_LoMin=(int)((longitude-m_LoDeg)*60);m_LoSec=(longitude-m_LoDeg-m_LoMin/60.)*3600;m_LaDeg=(int)latitude;m_LaMin=(int)((latitude-m_LaDeg)*60);m_LaSec=(latitude-m_LaDeg-m_LaMin/60.)*3600;m_Longitude=longitude;m_Latitude=latitude;m_RadLo=longitude*Math.PI/180.;m_RadLa=latitude*Math.PI/180.;Ec=Rj+(Rc-Rj)*(90.-m_Latitude)/90.;Ed=Ec*Math.cos(m_RadLa);}}
}
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