python输入城市名称_轻量级python库可以按邮政编码查询城市/州名称？

优点：数据是最新的、超级丰富的信息，比zipcode和pyzipcode和任何其他python zipcode库都要丰富和更新。

查询非常简单，您可以使用大约20+个内置查询模式。您可以自定义查询。

支持城市和州的模糊字符串匹配。你不需要使用确切的名字。>>> from uszipcode import ZipcodeSearchEngine

>>> search = ZipcodeSearchEngine()

>>> zipcode = search.by_zipcode("10001")

>>> print(zipcode)

{

"City": "New York",

"Density": 34035.48387096774,

"HouseOfUnits": 12476,

"LandArea": 0.62,

"Latitude": 40.75368539999999,

"Longitude": -73.9991637,

"NEBoundLatitude": 40.8282129,

"NEBoundLongitude": -73.9321059,

"Population": 21102,

"SWBoundLatitude": 40.743451,

"SWBoungLongitude": -74.00794499999998,

"State": "NY",

"TotalWages": 1031960117.0,

"WaterArea": 0.0,

"Wealthy": 48903.42702113544,

"Zipcode": "10001",

"ZipcodeType": "Standard"

}

# fuzzy city, state search, case insensitive, spelling mistake tolerant

# all zipcode in new york

>>> result = search.by_city_and_state(city="newyork", state="NY")

>>> search.export_to_csv(result, "result.csv")

很容易使用来建立高级搜索>>> result = search.find(city="new york",

... wealthy=100000, sort_by="Wealthy", ascending=False, returns=10)

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