Python 入门编程题（一）答案

Python 入门编程题：1~10（答案）

提示：最好还是先思考，先编写，再看答案哦 ^_^

1.

for i in range(1, 5):for j in range(1,5):for k in range(1, 5):if i != j and j!= k and i != k:print(i,j,k)

2.

i = int(input('净利润:'))
arr = [1000000,600000,400000,200000,100000,0]
rat = [0.01,0.015,0.03,0.05,0.075,0.1]
r = 0
for idx in range(0,6):if i > arr[idx]:r += (i - arr[idx]) * rat[idx]print((i-arr[idx]) * rat[idx])i = arr[idx]
print(r)

3.

import math
for i in range(10001):if math.sqrt(i + 100) == int(math.sqrt(i + 100)) and math.sqrt(i + 268) == int(math.sqrt(i + 268)):print(i)

4.

def leapyear(n):return True if (n % 4 == 0 and n % 100 != 0) or n % 400 == 0 else Falsedays = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 ]
year, month, day = [int(x) for x in input('input year/month/day: ').split('/')]
day2 = sum(days[:month - 1]) + day
if leapyear(year) and month > 2:day2 += 1
print(day2)

5.

L = []
a = int(input('请输入第一个整数：'))
b = int(input('请输入第二个整数：'))
c = int(input('请输入第三个整数：'))
L.append(a)
L.append(b)
L.append(c)
L.sort()
print(L)

6.

#斐波那契数列。
def fib(n):a,b = 1,1for i in range(n-1):a,b = b,a+breturn a

7.

#输出 9*9 乘法口诀表
for i in range(1, 10):for j in range(1, i+1):print('%s * %s = %s' %(i, j, i * j), end = '    ')print()

8.

import math
leap = 1
h = 0
for m in range(101, 201):k = int(math.sqrt(m + 1))for i in range(2, k+1):if  m % i == 0:leap = 0breakif leap == 1:print('%-4d' %m, end = '')h += 1if h % 10 == 0:print()leap = 1
print('The total is %d' % h)

9.

from math import sqrt
#判断n是否为素数
def isprime(n):if n <= 1:return 0m = int(sqrt(n))+1for x in range(2,m):if n%x == 0:return 0return 1
#利用递归分解n并打印质因数
def bprime(n):if isprime(n):print(n)else:x = 2while x <= int(n/2):if n%x == 0:print(x)return bprime(n/x)x = x + 1

10.

x2 = 1
for day in range(9,0,-1):x1 = (x2 + 1) * 2x2 = x1
print(x1)

（未完待续，持续更新）

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