C#字节转换为double方法

C#字节数组转换为double方法
byte[] ssdsd = new byte[] { 0x00, 0x00, 0x90, 0x02, 0x00, 0x00, 0x00, 0x00 };
byte[] ssdsd1 = new byte[] { 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};
double doubleValue = BitConverter.ToDouble(ssdsd,0);
double doubleValue1 = BitConverter.ToDouble(ssdsd1,0);

          // 摘要://     Returns a double-precision floating point number converted from eight bytes at//     a specified position in a byte array.//// 参数://   value://     An array of bytes.////   startIndex://     The starting position within value.//// 返回结果://     A double precision floating point number formed by eight bytes beginning at startIndex.//// 异常://   T:System.ArgumentException://     startIndex is greater than or equal to the length of value minus 7, and is less//     than or equal to the length of value minus 1.////   T:System.ArgumentNullException://     value is null.////   T:System.ArgumentOutOfRangeException://     startIndex is less than zero or greater than the length of value minus 1.

本文来自互联网用户投稿，文章观点仅代表作者本人，不代表本站立场，不承担相关法律责任。如若转载，请注明出处。 如若内容造成侵权/违法违规/事实不符，请点击【内容举报】进行投诉反馈！