Oracle MySQL Hive sql 求相关性系数 corr

MySQL所有版本：

CREATE TABLE `sample`  (`x` float NOT NULL,`y` float NOT NULL,`user_name` varchar(255)
) ;INSERT INTO `sample` VALUES (1, 10, 'zs');
INSERT INTO `sample` VALUES (2, 4, 'zs');
INSERT INTO `sample` VALUES (3, 5, 'zs');
INSERT INTO `sample` VALUES (6, 17, 'zs');
INSERT INTO `sample` VALUES (56, 32, 'ls');
INSERT INTO `sample` VALUES (45, 21, 'ls');
INSERT INTO `sample` VALUES (33, 11, 'ls');
INSERT INTO `sample` VALUES (27, 1, 'ls');

select a.user_name,sum((a.x - b.ax) * (a.y - b.ay))/((count(a.x) -1) * b.diva) corr from sample a 
join
(select user_name,avg(x) ax, avg(y) ay, (stddev_samp(x) * stddev_samp(y)) diva 
from sample group by user_name) b 
on a.user_name = b.user_name   
group by user_name;

结果：

Oracle版本：

select user_name,corr(x,y) corr from (
select 1 as x,10 as y,'zs' as user_name from dual
union all 
select 2 as x,4 as y,'zs' as user_name from dual
union all 
select 3 as x,5 as y,'zs' as user_name from dual
union all 
select 6 as x,17 as y,'zs' as user_name from dual
union all 
select 56 as x,32 as y,'ls' as user_name from dual
union all 
select 45 as x,21 as y,'ls' as user_name from dual
union all 
select 33 as x,11 as y,'ls' as user_name from dual
union all 
select 27 as x,1 as y,'ls' as user_name from dual)
group by user_name

结果：

Hive版本：和oracle差不多

select a.user_name,corr(a.x,a.y) corr from (
select 1 as x,10 as y,'zs' as user_name
union all 
select 2 as x,4 as y,'zs' as user_name
union all 
select 3 as x,5 as y,'zs' as user_name
union all 
select 6 as x,17 as y,'zs' as user_name
union all 
select 56 as x,32 as y,'ls' as user_name
union all 
select 45 as x,21 as y,'ls' as user_name
union all 
select 33 as x,11 as y,'ls' as user_name
union all 
select 27 as x,1 as y,'ls' as user_name) a
group by a.user_name

结果：

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