JAVA 猜拳小游戏

以前用C++写了个猜拳小游戏，这次做个JAVA版的…C++版的在这里→http://blog.csdn.net/lingle77/article/details/41421769

又想起了已经离开的213同学。

代码如下

import java.util.Scanner;public class PlayGame {public static void main(String[] args) {System.out.print("scissor(0), rock(1), paper(2) :");int computer = (int) (Math.random() * 3);Scanner in = new Scanner(System.in);int user = in.nextInt();switch (computer) {case 0:System.out.print("The computer is scissor.");break;case 1:System.out.print("The computer is rock.");break;case 2:System.out.print("The computer is paper.");break;}System.out.print((user == 0) ? "You are scissor.": (user == 1) ? "You are rock.": (user == 2) ? "You are paper.": "\nInput error, please re-enter.");if (user == computer) {System.out.println(",the same with computer.It is draw.");} else if (user == ++computer || (user == 0 && computer == 2)) {System.out.println("You win.");} else if (user >= 0 && user <= 3)System.out.println("You lose.");}
}

运行结果

scissor(0), rock(1), paper(2) :0
The computer is paper.You are scissor.You lose.

scissor(0), rock(1), paper(2) :1
The computer is scissor.You are rock.You win.

总算刷了个平局出来：

scissor(0), rock(1), paper(2) :2
The computer is paper.You are paper.,the same with computer.It is draw.

scissor(0), rock(1), paper(2) :6
The computer is paper.
Input error, please re-enter.

学习心得

要产生随机数，可以使用Java api中java.lang包中的Math类.Math类以静态方法的方式提供常用的数学方法，
其中Math.random()方法是一个可以产生[0.0,1.0]区间内的一个双精度浮点数的方法
如：
产生一个100以内的整数：int x=(int)(Math.random()*100);
又如：
产生一个1-50之间的随机数：int x=1+(int)(Math.random()*50)

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