520表白爱心树代码,太美了,快发给女朋友看看

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今天给大家分享一个520表白爱心树代码实现效果!

看到上面效果是不是有被惊艳到,但是要实现这么炫酷的效果也实属不易啊!代码总共1万行左右,可以说是相当的哇塞了!

 部分代码展示:

function cv(a) {if (!ck[a]) {var b = c.body,d = f("<" + a + ">").appendTo(b),e = d.css("display");d.remove();if (e === "none" || e === "") {cl ||((cl = c.createElement("iframe")),(cl.frameBorder = cl.width = cl.height = 0)),b.appendChild(cl);if (!cm || !cl.createElement)(cm = (cl.contentWindow || cl.contentDocument).document),cm.write((c.compatMode === "CSS1Compat" ? "" : "") +""),cm.close();(d = cm.createElement(a)),cm.body.appendChild(d),(e = f.css(d, "display")),b.removeChild(cl);}ck[a] = e;}return ck[a];}function cu(a, b) {var c = {};f.each(cq.concat.apply([], cq.slice(0, b)), function () {c[this] = a;});return c;}function ct() {cr = b;}function cs() {setTimeout(ct, 0);return (cr = f.now());}function cj() {try {return new a.ActiveXObject("Microsoft.XMLHTTP");} catch (b) {}}function ci() {try {return new a.XMLHttpRequest();} catch (b) {}}function cc(a, c) {a.dataFilter && (c = a.dataFilter(c, a.dataType));var d = a.dataTypes,e = {},g,h,i = d.length,j,k = d[0],l,m,n,o,p;for (g = 1; g < i; g++) {if (g === 1)for (h in a.converters)typeof h == "string" && (e[h.toLowerCase()] = a.converters[h]);(l = k), (k = d[g]);if (k === "*") k = l;else if (l !== "*" && l !== k) {(m = l + " " + k), (n = e[m] || e["* " + k]);if (!n) {p = b;for (o in e) {j = o.split(" ");if (j[0] === l || j[0] === "*") {p = e[j[1] + " " + k];if (p) {(o = e[o]), o === !0 ? (n = p) : p === !0 && (n = o);break;}}}}!n &&!p &&f.error("No conversion from " + m.replace(" ", " to ")),n !== !0 && (c = n ? n(c) : p(o(c)));}}return c;}function cb(a, c, d) {var e = a.contents,f = a.dataTypes,g = a.responseFields,h,i,j,k;for (i in g) i in d && (c[g[i]] = d[i]);while (f[0] === "*")f.shift(),h === b &&(h = a.mimeType || c.getResponseHeader("content-type"));if (h)for (i in e)if (e[i] && e[i].test(h)) {f.unshift(i);break;}if (f[0] in d) j = f[0];else {for (i in d) {if (!f[0] || a.converters[i + " " + f[0]]) {j = i;break;}k || (k = i);}j = j || k;}if (j) {j !== f[0] && f.unshift(j);return d[j];}}

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