Covfefe【难度:1级】:
答案1:
def covfefe(s):return s.replace("coverage","covfefe") if "coverage" in s else s+" covfefe"
答案2:
def covfefe(s):return s.replace('coverage', 'covfefe') if 'coverage' in s else s + ' covfefe'
答案3:
def covfefe(s):return s.replace('coverage','covfefe') if 'coverage' in s else s+" covfefe"
答案4:
def covfefe(s):return s.replace("coverage", "covfefe") if "coverage" in s else (s+" covfefe")
答案5:
def covfefe(s):return s.replace("coverage", "covfefe") if "coverage" in s else (s + " covfefe")
答案6:
def covfefe(s):return s.replace("coverage", "covfefe") if ("coverage" in s) else s + " covfefe"
答案7:
def covfefe(s):return (s.replace("coverage", "covfefe") if "coverage" in s else s+" covfefe")
答案8:
def covfefe(s):return s.replace("coverage", "covfefe") if "coverage" in s else s + " covfefe"
答案9:
def covfefe(s):if 'coverage' in s:return s.replace('coverage', 'covfefe')else:return s + ' ' + 'covfefe'
答案10:
def covfefe(s):return "".join(s.replace("coverage", "covfefe") if "coverage" in s else s + " covfefe")
答案11:
def covfefe(s):t = s.replace("coverage", "covfefe")return t + " covfefe"*(len(t) == len(s))
答案12:
def covfefe(s):return s.replace('coverage', 'covfefe') if s.__contains__('coverage') else s + ' covfefe'
答案13:
covfefe = lambda s: s.replace("coverage", "covfefe") if "coverage" in s else s + " covfefe"
答案14:
covfefe = lambda s: s.replace('coverage', 'covfefe') if 'coverage' in s else s + ' covfefe'
答案15:
def covfefe(stg):return stg.replace("coverage", "covfefe") if ("coverage" in stg) else f"{stg} covfefe"
答案16:
def covfefe(s): if s.find("coverage") == -1:return s + " " + "covfefe"return s.replace("coverage", "covfefe")
答案17:
import re
def covfefe(s):r, n = re.subn('coverage', 'covfefe', s)return r + ' covfefe' * (n == 0)
答案18:
def covfefe(s):return (s + ' coverage' * ('coverage' not in s)).replace('coverage', 'covfefe')
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