Problem C: 克隆人来了！
Problem C: 克隆人来了！
Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 896 Solved: 507
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Description
克隆技术飞速发展，克隆人已经成为现实了！！所以，现在由你来编写一个Person类，来模拟其中的克隆过程。这个类具有2个属性：name——姓名（char*类型），和age——年龄（int类型）。
该类具有无参构造函数（人名为“no name”，年龄是0）、带参数构造函数、拷贝构造函数以及析构函数外，还有以下3个成员函数：
1. void Person::showPerson()：按照指定格式显示人的信息。
2. Person& Person::setName(char *)：设定人的姓名。
3. Person& Person::setAge(int)：设定人的年龄。
Input
输入分多行，第一行是一个正整数N，表示其后有N行输入。每行分两部分：第一部分是一个没有空白符的字符串，表示一个人的姓名；第二部分是一个正整数，表示人的年龄。
Output
呃~比较复杂，见样例吧！注意：要根据样例编写相应函数中的输出语句，注意格式哦！
Sample Input
3 Zhang 20 Li 18 Zhao 99
Sample Output
A person whose name is "no name" and age is 0 is created! A person whose name is "Tom" and age is 16 is created! A person whose name is "Tom" and age is 16 is cloned! A person whose name is "Zhang" and age is 20 is created! This person is "Zhang" whose age is 20. A person whose name is "Zhang" and age is 20 is erased! A person whose name is "Li" and age is 18 is created! This person is "Li" whose age is 18. A person whose name is "Li" and age is 18 is erased! A person whose name is "Zhao" and age is 99 is created! This person is "Zhao" whose age is 99. A person whose name is "Zhao" and age is 99 is erased! This person is "Zhao" whose age is 18. This person is "no name" whose age is 0. A person whose name is "Zhao" and age is 18 is erased! A person whose name is "Tom" and age is 16 is erased! A person whose name is "no name" and age is 0 is erased!
HINT
注意：输出中有“”！
Append Code
#1：用到了拷贝构造函数，形参为一个对象的引用； #2：同样的类成员可以互相赋值，像该题的name如果用strcpy函数就会出现运行错误。 #3：
Person& setName(char *p)和Person& setAge(int p)的返回值类型为Person的引用，如果不加引用符号会出现未知错误（不懂其原因）。 #4：输出双引号需要加"\"符号，和c语言相同。
代码如下：
#include
#include
using namespace std;
class Person
{
private: char *name; int age;
public: Person():name("no name"),age(0){cout<<"A person whose name is "<<"\""<<"no name"<<"\""<<" and age is "<<0<<" is created!"<>cases; for (int ca = 0; ca < cases; ca++) { cin>>str>>age; Person newPerson(str, age); newPerson.showPerson(); } anotherTom.setName(str).setAge(18); anotherTom.showPerson(); noname.showPerson(); return 0;
}
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